Math, asked by sandeep328, 1 year ago

find quadratic polynomial if zeroes are
-√5/4 , √3/3

Answers

Answered by Khushi0511
8
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Answered by Anonymous
1

The quadratic polynomial whose zeroes are,

5 \sqrt{3} ,5 -  \sqrt{3}

 \alpha , \beta  \: is \: f(x) = k[ {x}^{2} - ( \alpha  +  \beta )x +  \alpha  \times  \beta  ]

where k is any non-zero real no.

THE QUADRATIC POLY POLYNOMIAL WHOSE ZEROES ARE

5 \sqrt{3} ,5 -  \sqrt{3}

 f(x) = k[ {x}^{2} - ( \alpha  +  \beta )x +  \alpha  \times  \beta  ]

 f(x) = k[ {x}^{2} - ( 5  \cancel{ +  \sqrt{3}}  + 5  \cancel{ -  \sqrt{3}} )x +    (5 +  \sqrt{3}   ) (5 -  \sqrt{3}  ) ]

 f(x) = k[ {x}^{2} -10x + ( {5)}^{2}  -  ({ \sqrt{3} )}^{2}  ]

 f(x) = k[ {x}^{2} -10x + (25  - 3)]

 f(x) = k[ {x}^{2} -10x + 22]

so, the QUADRATIC polynomial is

 f(x) = k[ {x}^{2} -10x + 22]

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