mihir and varun have surface areas of their palms as 15 × 10 ^- 4 m square and 25 × 10 ^-4 m square respectively how much thrust they need to apply so that pressure on their palms is 30000 pascal
Answers
Answered by
3
surface area of mihir palm = 15 × 10 ^-4 m2
surface area of varun palm = 25 × 10 ^-4 m2
for mihir:
since pressure = force / area
=> 30000 pa= force / 15 × 10^-4 m2
=> force = 30000 pa × 15 × 10 ^ -4 m2
therefore force = 45 N
hence a force of 45 N is required to make a pressure of 30000 pascal on mihir's palm
for varun:
since pressure = force / area
=> 30000 pa= force / 25 × 10^-4 m2
=> force = 30000 pa × 25 × 10 ^ -4 m2
therefore force = 75 N
hence a force of 75 N is required to make a pressure of 30000 pascal on varun's palm
surface area of varun palm = 25 × 10 ^-4 m2
for mihir:
since pressure = force / area
=> 30000 pa= force / 15 × 10^-4 m2
=> force = 30000 pa × 15 × 10 ^ -4 m2
therefore force = 45 N
hence a force of 45 N is required to make a pressure of 30000 pascal on mihir's palm
for varun:
since pressure = force / area
=> 30000 pa= force / 25 × 10^-4 m2
=> force = 30000 pa × 25 × 10 ^ -4 m2
therefore force = 75 N
hence a force of 75 N is required to make a pressure of 30000 pascal on varun's palm
Answered by
1
Answer:
mihir=45N
varun=75N
Explanation:
surface area of mihir palm =15×10^-4 m^2
surface area of vain palm =25×10^-4 m^2
for mihir :
=>since pressure = force/area
=30000 pa =force/15×10^-4 m^2
=force =30000 pa ×15×10^-4 m^2
therefore force =45N
for varun :
=>since pressure =force/area
=30000 pa =force/25×10^-4 m^2
=force=30000 pa ×25×10^-4 m^2
therefore force =75N
Similar questions