Question

Find quadratic polynomial whose zeroes are 3 and 2/5

Answer 1

Answer:

Sum of zeroes = 3 + 2/5

= 15 + 2 / 5

= 17/ 5

Product of zeroes = 3(2/5)

= 6/5

Therefore , quadratic polynomial =

x*2 - 17/ 5 x+ 6 / 5 = 0

5 x*2 - 17x + 6 = 0

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Answer 2

Answer:

The final answer is $x^2$ $+$ $17/5x$ $+$$6/5$

Step-by-step explanation:

There is a simple way to find a quadratic equations with zeroes = 3 and 2/5.

Let $\alpha$ be the sum of zeroes.

Let $\beta$ be the product of zeroes.

Then, the quadratic equation will look like

$x^2 + \alpha x + b$

$\alpha$ = 3 + 2/5 = 15/5 + 2/5 = 17/5

$\beta$ = 3 * 2/5 = 6/5

Now we simply substitute the given terms in the above equation we get,

$x^2$ $+$ $17/5x$ $+$$6/5$

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