Question

xsquare _2x+1=0 roots of the quadratic equation​

Answer 1

Answer:

Given eq. = x^2 - 2x + 1 = 0

x^2 - 1x - 1x + 1 = 0

x(x - 1) -1(x - 1) = 0

(x - 1) (x - 1) = 0

x = 1, x = 1

Thus, the given eq. has two equal real roots.