Question

find quadratic polynomial whose zeros are - 4 and 3

Answer 1

Zeroes are - 4 and 3

Sum of zeroes = - 4 + 3 = - 1

Product of zeroes = (-4) (3) = - 12

Required polynomial is x^2 - (sum of zeroes)x + (Product of zeroes)

= x^2 - (-1) x + (-12)

= x^2 + x - 12

Answer 2

$\alpha + \beta = - b \div a \\ \: \\ \alpha \times \beta = c \div a$
-4+3=-1
_4×3=(-12)
a=1;b=1;c=-12
${x}^{2} + x - 12 \: is \: ur \: quadrticequtn$