Question

Find quadratic polynomial zeroes are -3 and 6?
Please donot give rubbish answer!!

Answer 1

if we have sum of roots =S
and product of roots =p
then general equation is given by
${x}^{2} - sx + p= 0$
here sum=s=-3+6=3
p=(-3)(6)=-18
therefore equation is
${x}^{2} - 3x - 18 = 0$
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method 2:
two roots are given
therefore factors are
$(x + 3)(x - 6)$
solve it
(x^2-6x+3x-18)=0
x^2-3x-18=0