CBSE BOARD XII, asked by DhawalDutta, 11 months ago

Find: question number 8

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Answered by pal69

0

Answer:

£sin³x +cos³x/(sin²x.cos²x) dx

£sin³x/sin²x.cos²x +cos³x/sin²x.cos²x dx

£secx. tanx +cosecx.cotx dx

secx -cosecx+C

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