Find r^th term of an A.P. whose sum of first n terms is 2n+3n^2.
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Given that sum of n terms of an AP.
Sn = 2n + 3n²
Tn = Sn-Sn-1
= (2n + 3n²) − [2(n − 1) + 3(n − 1)²]
= (2n + 3n²) — [2n − 2 + 3(n² + 1 − 2n)]
= (2n + 3n²) - (2n − 2 + 3n² + 3 − 6n)
= 2n + 3n²2n + 2- 3n²-3+ 6n
= 6n - 1
rthterm Tr = 6r- 1
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