Question

find range of projectile on the inclined plane which is projected perpendicular to the incline plane wth velocity 20m/s .angle=37°​

Answer 1

Hey Dear,

◆ Answer -

R = 77 m

● Explaination -

# Given -

u = 20 m/s

θ = 37°

# Solution -

Range of projectile on the inclined plane is calculated by formula -

R = 2.u².sinθ / g.cos²θ

R = (2 × 20² × sin37°) / (9.8 × cos²37°)

R = (2 × 400 × 0.6018) / (9.8 × 0.7986^2)

R = 77 m

Therefore, range of the projectile on inclined plane is 77 m.

Thanks for asking...

Answer 2

Answer:

75 m.

Explanation:

acceleration due to gravity taken as 10m/s²

For Horizontal Range we have to consider motion in x - axis (direction)

u in x = u cos alpha = 20 × cos 90 = 0m/s

a in x = g sin theta = 10sin37 = 10 × 3/5 = 6m/s²

for time, consider motion in y as :

u in y = u sin alpha = 20 × sin 90 = 20m/s

a in y = g cos theta = 10 × cos37 = 10 × 4/5 = 8m/s²

So,

T = 2u sin alpha/g cos theta = 2 × 20/8 = 5 s

Hence,

Horizontal range

(R) = ut + 1/2 at² ( u in x and a in x )

(R) = 0 × 5 + 1/2 × 6 × (5)²

(R) = 3 × 25

(R) = 75m