Find range of y= f(x) =x+1
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Domain of f(x) is −1≤x≤4
Given , g(x)=4−3f(x−2)
Here , −1≤x−2≤4
⇒1≤x≤6
So, domain of g(x) is [1,6]. a=1,b=6
Range of f(x) is 1≤f(x)≤10
⇒1≤f(x−2)≤10
⇒3≤3f(x−2)≤30
⇒−30≤−3f(x−2)≤−3
⇒−26≤4−3f(x−2)≤1
So,c=−26,d=1q
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