Question

Two resistances of 4Ω and 6Ω are connected in parallel and then in series with another
resistance of 12Ω. If the current flowing in 12Ω resistance is 2A. determine (i) the current
flowing through 4Ω and 6Ω resistors (ii) voltage across the whole circuit and (iii) power
drawn from the supply.

Answer 1

Explanation:

Total current I flowing through the circuit I=

R

V

Here R=equivalentresistance=3.03Ω-----refer the figure given.

I

total

=

3.03

5

=1.65A

Since the resistors are in series connection (fig. B) current I will flow equally throughout the circuit.

Now calculating for voltage in resistor of 2Ω

V

B

=IR=3.30V, then current I flowing through 6Ω resistor I

6

=

6

3.30

=0.55