Question

Find Rate of Interest (R) & Simple Interest (SI) if

Principal (P) = 12000,
Time (T) = 13years
Amount (A) = 15500


Please Give Full Solution​

Answer 1

Answer:

SI = ₹ 3500

R = $2\dfrac{19}{78}\%\;p.a$

Step-by-step explanation:

Given that,

Principal (P) = ₹ 12000

Time (T) = 13 yrs.

Amount (A) = ₹ 15500

To find the Rate of Interest (R) and Simple Intrest (SI).

We know that,

SI = P × R × T/100

Substituting the values,

Therefore, we will get,

=> SI = 12000 × R × 13/100

=> SI = 120 × 13 × R

=> SI = 1560R

Also, we know that,

A = P + SI

Substituting the values, we get,

=> 15500 = 12000 + 1560R

=> 1560R = 15500 - 12000

=> 1560R = 3500

=> R = 3500/1560

=> R = 350/156

=> R = 175/78

Therefore, we will get,

=> SI = 1560 × 175/78

=> SI = 20 × 175

=> SI = 3500

Hence, the required Simple Intrest (SI) and Rate of Interest (R) is ₹ 3500 and $\bold{2\dfrac{19}{78}\%\;p.a}$

Answer 2

$\maltese$ ${\red{\bold{\underline{SOLUTION : }}}}$ $\maltese$

Given that,

•Principal (P) = Rs. 12000

•Time (T) = 13 years.

•Amount (A) = Rs. 15500

Now , we have to find the Rate of Interest (R) and Simple Intrest (SI).

We know that,

SI = P × R × T/100

[Putting the values ]

=> SI = 12000 × R × 13/100

=> SI = 120 × 13 × R

=> SI = 1560R .

As, we know that,

A = P + SI

[Putting the values ]

=> 15500 = 12000 + 1560R

=> 1560R = 15500 - 12000

=> 1560R = 3500

=> R = 3500/1560

=> R = 350/156

=> R = 175/78 .

Now,

=> SI = 1560 × 175/78

=> SI = 20 × 175

=> SI = 3500 .

Therefore, the required Simple interest and Rate of Interest is respectively Rs.3500 and 2 19/78% p. a.