Question

Find ratio in which line x-y-2=0 divides the line

Answer 1

in ratio 2:3

Step-by-step explanation:

let A( 3 , -1 )and B (8,9 )

let the line x -y- 2= 0 divide the line segment AB at point c (x ,y )in the ratio m:n

by section formula c x y (m×8 n 3 ) /( m 9 n 1 )

m +n / m +n

8m +3n / 9m- n

m+ n / m+ n

since point c x y lie on line x -y- 2= 0

8m +3n/ 9m -n

m +n / m +n 2 0

8m+ 3n- 9m+ n --2m- 2n= 0

3m+ 2n =0

3m =2n

m = 2/n= 3

hence line x - y -2 =0

divide the line segment

joining A( 3 ,1) and B( 8, 9 )

in ratio 2 : 3