Find real roots of : x²+kX+4=0
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Answer:
what is real root first tell this then I will solve your query ok
Answered by
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Answer:
K = +4 and -4
Explanation:
Given: polynomial x² − kx + 4 = 0, has equal real roots
To find the value of k
we know, A quadratic equation has equal real roots if the discriminant b² − 4ac = 0
x² − kx + 4 = 0 is of form ax² + bx + c = 0
Thus, a = 1 , b = − k , c = 4
Hence the discriminant is
( − k )² − 4 * ( 1 ) * ( 4 ) = 0
k² − 16 = 0
k² = 16
Therefore, k = ± 4
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