Question

Find real sol. Of the equation:--

tan^-1√x(x+1) + sin^-1√x^2+x+1 = π/2

Answer 1

Step-by-step explanation:

frnd I can't understand this question

Answer 2

Your answer mate

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tan-1[x2+x]1/2 + sin-1[x2+x+1]1/2 = pi/2

= tan-1[x2+x]1/2 + sin-1[x2+x+1]1/2 = sin-1[x2+x+1]1/2 + cos-1[x2+x+1]1/2

= tan-1[x2+x]1/2 = cos-1[x2+x+1]1/2

= cos-1[1/(x2+x+1)1/2] = cos-1[x2+x+1]1/2

= 1/ (x2+x+1)1/2 =[ x2+x+1]1/2

= x2+x+1 = 1

= x2+x = 0

=x(x+1)  =>  x=0 or x = -1

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