Question

find rectangular component of force of 4N when one of component makes an angle of 60 with force itself​

Answer 1

Step-by-step explanation:

We realize that F(x) = F•cosa and F(y) = F•sina where an is the edge anf F is the Force

Here a= 60 degrees and F=4N

By utilizing F(x) = F•cosa

F(x) = 4 . cos 60

4/2 = 2

Henceforth F(x) is equivalent to 2

By utilizing F(y) = F•sina

F(y) = 4 . sin 60

4(√3/2 )= 2√3

Henceforth F(y) is equivalent to 2√3

Answer 2

Answer:

Follow for more answer

Step-by-step explanation:

We realize that F(x) = F•cosa and F(y) = F•sina where an is the edge anf F is the Force

Here a= 60 degrees and F=4N

By utilizing F(x) = F•cosa

F(x) = 4 . cos 60

4/2 = 2

Henceforth F(x) is equivalent to 2

By utilizing F(y) = F•sina

F(y) = 4 . sin 60

4(√3/2 )= 2√3

Henceforth F(y) is equivalent to 2√3