find reduced form of ratio of quantity to quantity 7 min 20 sec ,5 min 6 sec
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Answered by
4
7 min 20 sec = 420 + 20 = 440 second
5 min 6 sec = 300 + 6 = 306 second
440 = 2 × 2 × 2 × 5 × 11
306 = 2 × 3 × 3 × 3 × 17
HCF = 2
Required ratio = (440 /2) /(306/2)
= 220 / 153
= 220 : 153
Answered by
2
Answer:
220 : 153
Step-by-step explanation:
7 mins 20 secs = 420 + 220 = 440 secs
5 mins 6 secs = 300 + 6 = 306 secs
440 = 2 × 2 × 2 × 5 × 11
306 = 2 × 3 × 3 × 17
HCF = 2 × 2 = 4
440/306 = (440÷2)/(306÷2)
= 220/153
= 220 : 153
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