Chemistry, asked by Arham10187, 1 year ago

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Answered by LUCIFER800
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THE REACTION HERE IS KNOWN AS ESTERIFICATION REACTION

C₂H₅OH + CH₃COOH  → CH₃COOC₂H₅ +H₂O

EHTANOL + ETHANOIC ACID  →  ESTER +WATER

ELEMENT       REACTANT        PRODUCT

C                           3                               3

H                          10                              10

O                           3                                3

HERE IN THE REACTION ETHANOL REACT WITH ETHANOIC ACID TO FORM ESTER AND WATER

HOPE IT HELPS

THANKS

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