Question

find relation between operators
∆=E-1 ​

Answer 1

Step-by-step explanation:

Relations between the operators Δ, ∇ and E:

Δ ≡ E −1. Proof: From the definition of Δ we know that. Δ f (x) = f (x + h ) − f (x) and. E[ f (x )] = f (x + h) where h is the interval of difference. Δ f (x) = f (x + h ) − f (x) Δ f (x) = Ef (x ) − f (x) ...

Δ E ≡ Δ E. Proof: E(Δf(x)) = E[f(x+h)- f(x)] = E f(x+h) - E f(x) = f(x+2h) - f(x+h) =Δf(x+h) =ΔEf(x) ...

∇≡ E −1 / E.