Find remainder when x^2+3x^2+3x+1
is divided by 5+2x
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x^2+3x^2+3x+1 is divided by 5 + 2x
First we need to make 5+2x as a perfect value to find the remainder of the equation
So,5+2x=0
2x=-5
x=-5/2.
We got x value now substitute the value in x place of equation
x^2+3x^2+3x+1
(-5/2)^2+3(-5/2)^2+3(-5/2)+1
{(25/4)+(75/4)}+{(-15/2)+1}
(100/4)+(-13/2)
25-13/2
50-13/2
37/2
So, it is not a perfect remainder
But overall,you get 37/2 is the remainder
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