Question

Find resultant of 2Ω, 3Ω and 6Ω resistors connected in parallel.

Answer 1

Answer:

Read explanation

Explanation:

1. Methodology:- Please first remember the below formula,

1/R=1/R1 + 1/R2 +1/R3

1/R= 1/2 + 1/3 + 1/6

1. 1/R= 1 => R=1ohm
2. If you dream IIT:- You will later come to know that, to solve more complex circuits, some laws such as Kirchoffs law are used, its all in 11th or 12th class

Answer 2

Answer:

Given that - R1 = 2 ohm

R2 = 3 ohm

R3 = 6 ohm

as ber by parallel combination ,

1 / Req = 1 / R1 + 1 / R2 + 1 / R3

1 / Req = 1 / 2 + 1 / 3 + 1 / 6

1 / Req = ( 3 + 2 + 1 ) / 6 = 6 / 6 = 1 / 1

Req = 1 ohm

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