Question

Find rhe greatest number of six digits exactly divisible by 18, 24 and 36

Answer 1

Answer:

greatest number of six digits exactly divisible by 18, 24 and 36 = 999936

Step-by-step explanation:

take l. C.M GIVE NUMBERS

18 = 2×3×3

24=2×2×2×3

36=2×2×3×3

lCM = 2×2×2×3×3 = 72

take greatest number of six digit = 999999

divided by 72 .

999999/72 =

$13888 \frac{63}{72}$

then 999999-63 = 999936

greatest number of six digits exactly divisible by 18, 24 and 36 = 999936