Question

Find rhe Pythagorean triplets whose smallest member is 18

Answer 1

hey dear


here is your answer


___________________________________

smallest number 18



formula of Pythagoran triplet

( 2m , m^2 -1 , m^2+1 )



2m = 18


m = 18 / 2


m = 9




so,


m^2 - 1 = ( 9)^2 -1 = 81 -1 = 80


m^2 + 1 = ( 9 )^2 + 1 = 81 +1 = 82



hence Pythagoran triplet are


( 9 , 80 , 82 )

___________________________________¥



hope it helps

thank you

Answer 2

Answer:

lol

Step-by-step explanation:

l + o + l

= lol