Find rhe smallest number exactly dvisible by 12,24,32.
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Smallest number exactly divisible by 12,20,224 and 32 is their LCM. LCM is given by the product of prime factors, each raised by the highest exponent. As 2 occur maximum 5 times, 3 and 5 occur one time each. Hence, the required smallest number is 480.
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find the lcm of these numbers then only you get answer
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