Question

find roots of following equation (x+3)(x-1=3 (x-1/3)

Answer 1

Answer:

$x=2$ and $x=-1$ are the roots of the given quadratic equation

Step-by-step explanation:

The given quadratic equation:

$(x+3)(x-1)=3(x-\frac{1}{3} )$

$(x+3)(x-1)=3x-\frac{3}{3}$

$x^{2} +3x-x-3=3x-1$

$x^{2} -x-2=0$

$x^{2} -2x+x-2=0$

$x(x-2)+1(x-2)=0$

$(x+1)(x-2)=0$

$x=2$  or $x=-1$

Hence, $x=-1$ and $x=2$ are the roots of the quadratic equation