Math, asked by shrugodase7711, 2 months ago

find roots of
4 {x}^{2} + 3x - 28 = 0
by completing square​

Answers

Answered by mohddaniyal794
0

Answer:

The solutions are:

x

=

4

,

x

=

7

Explanation:

x

2

3

x

28

=

0

We can first factorise this expression by splitting the middle term and then find the solutions:

=

x

2

7

x

+

4

x

28

=

0

=

x

(

x

7

)

+

4

(

x

7

)

=

0

=

(

x

+

4

)

(

x

7

)

Now, we can equate the two factors with zero and find the solutions:

x

+

4

=

0

,

x

=

4

x

7

=

0

,

x

=

7

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