Question

find roots of the following quadratic equations by factorization method, 2ax^2-(2a-b^2)x-b^2=0​

Answer 1

Answer:

2ax^2-(2a-b^2)x-b^2=0

=> 2ax^2-2ax+b^2x-b^2=0

=> 2ax(x-1)+b^2(x-1)=0

=> (x-1)(2ax+b^2)=0

=> x-1=0

=> x=1

again,

2ax+b^2=0

=> 2ax= -b^2

=> x= -b^2/2a

so, x=1 and x= -b^2/2a