find roots of the quadratic equation x²-2x+3.
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Answered by
12
Heya !!!
P(X) = X² - 2X - 3
=> X² - 3X + X - 3
=> X ( X - 3) + 1 ( X - 3)
=> ( X - 3) ( X + 1) = 0
=> ( X -3) = 0 OR ( X + 1) = 0
=> X = 3 OR X = -1
Hence,
3 and -1 are the roots of the quadratic polynomial X² - 2X - 3.
★ HOPE IT WILL HELP YOU ★
P(X) = X² - 2X - 3
=> X² - 3X + X - 3
=> X ( X - 3) + 1 ( X - 3)
=> ( X - 3) ( X + 1) = 0
=> ( X -3) = 0 OR ( X + 1) = 0
=> X = 3 OR X = -1
Hence,
3 and -1 are the roots of the quadratic polynomial X² - 2X - 3.
★ HOPE IT WILL HELP YOU ★
Answered by
0
here is your answer
x^2-2x-3
x²-3x+x-3
x(x-3)+1(x-3)
(x-3)(X+1)
x=3 , x=-1
Hope it helps you ^_^
Mark as brainliest
x^2-2x-3
x²-3x+x-3
x(x-3)+1(x-3)
(x-3)(X+1)
x=3 , x=-1
Hope it helps you ^_^
Mark as brainliest
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