Find roster form of set A
A = { x : 2x+1 , x ∈ N , x ≤ 5}
Give a satisfactory explanation
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A = { x : 2x + 1 , x € N , x ≤ 5 }
A = { 1 , 2 , 3 , 4 , 5 }
2×1 + 1 = 2 + 1 = 3
2×2 + 1 = 4 + 1 = 5
2×3 + 1 = 6 + 1 = 7
2×4 + 1 = 8 + 1 = 9
2×5 + 1 = 10 +1 = 11
Here the final answer
A = { 1 , 2 }
A = { 3 , 5 }
A = { 1 , 2 , 3 , 4 , 5 }
2×1 + 1 = 2 + 1 = 3
2×2 + 1 = 4 + 1 = 5
2×3 + 1 = 6 + 1 = 7
2×4 + 1 = 8 + 1 = 9
2×5 + 1 = 10 +1 = 11
Here the final answer
A = { 1 , 2 }
A = { 3 , 5 }
LilyWhite:
ya
sure
bcoz it came for 4 marks today in math exam class 10 Telangan
but here 2x+1 is there so A = { 3 , 5 }
but 2x+1 should be a natural no. that is the rule. not 2x+1 less than or equal o 5
ya i have given down answers no then
A = { 3 , 5 } is the correct answer
what is the final answer A=(3,5) or A=(1,2,3,4,5)
A = { 3 , 5 }
sry
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