Question

find S10 ,if a= 6, d=3​

Answer 1

S10 = n/2+(2a+(n-1)d

S10=10/2+(2×6+(10-1)3

S10=5+(12+9×3

S10=5+(12+27)

S10=5+39=44

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Answer 2

Answer:

Given,

n=10

a=6

d=3

we know that---

Sn=n/2[2a+(n-1)d]

S10=10/2[2×6+(10-1)3]

S10=5[12+27]

S10=5×39

S10=195..

Step-by-step explanation:

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