Math, asked by ibadaziz9968, 11 months ago

Find sec 15/ cosec 75 + sin 72/ cos 18 - tan 38/ cot 57

Answers

Answered by srilakshmi23
20

hope it helps you..............

Attachments:
Answered by prabhashankar330
5

Answer:

Step-by-step explanation:

Sec15/Sec74 + Sin 72/cos 18 - tan33/cot 57

sec15/Sec74 + sin72/cos(90-18) - tan 33/ cot(90-57)

sec15/sec 74 + sin72/sin72 - tan 33/tan 33

sec 15/sec 74 +1-1

sec 15/sec 74

The question is wrong...bcz the 1st's down portion should be cosec75.

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