Question

Find simple interest when principal=5000, rate=8%p.a. and time=439 days

Answer 1

Rate of Interest for a day = 8/365 = 0.021 %

S.I. = PRT/100
= 5000×0.021×439/100
= 460.91 rs.

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=481.09\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 439\: days} \\ \\ : \implies \text{Principal(p) = 5000\:rupees} \\ \\ : \implies \text{Rate(r) = 8\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{5000 \times 8 \times\frac{439} {365} }{100} \\ \\ : \implies S.I = \frac{50\times3512 }{365} \\ \\ \green{ : \implies \text{S.I= 481.09\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =481.09\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$