Question

Find sin(270 + theta) and cos(270 + theta)

Answer 1

Hey there! ☺☻☺

sin (270° + θ) = sin [1800 + 90° + θ]

                      = sin [1800 + (90° + θ)]    

As (90+θ) = cos θ

∴ sin (270+θ)  = - sin (90° + θ)

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cos (270° + θ) = cos [1800 + 90° + θ]

                    = cos [1800 + (90° + θ)]

As cos(90 +θ) = - sin θ 

∴ cos (270+θ) = - cos (90° + θ)

Hope it Helps You! ☺☻☺

Answer 2

Answer:

Hey there!

sin (270° + θ) = sin [1800 + 90° + θ]

                      = sin [1800 + (90° + θ)]    

As (90+θ) = cos θ

∴ sin (270+θ)  = - sin (90° + θ)

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cos (270° + θ) = cos [1800 + 90° + θ]

                    = cos [1800 + (90° + θ)]

As cos(90 +θ) = - sin θ 

∴ cos (270+θ) = - cos (90° + θ)

Hope it Helps You!

Stay blessed✨