Find sin^30×cos^45+4 tan^30+1/2 sin^90+1/8×cot^60
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sin30=1/2
therefore, sin²30=1/4......(1)
cos45=√2
cos²45=2................. (2)
tan 30 =1/√3
tan²30=1/3.......(3)
sin90=1
sin²90=1......... (4)
cot 60=1/√3
cot²60=1/3..........(5)
therefore by substituting the values,
sin²30×cos²45+4×tan²30+1/2+sin²90+1/8×cot²60
1/4×2+4×1/3+1/2+1+/8×1/3
1/2+4/3+1/2++1/8×1/3
37/24
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