find sin 74 using sin a + b is equal to sin a cos b + cos a sin b
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Sin 75°= Sin (30° + 45°)
= Sin 30° Cos 45° + Sin 45° Cos 30°
= (1 / 2) (1 / √2) + (1 / √2) (√3 / 2)
= (1 / 2√2) + (√ 3 / 2 √2)
= (1 + √3) / 2 √2
On rationalising :-
(1 + √3) (2 √2) / (2√2) (2√2)
(2 √2 + 2 √6) / 8
2 (√2 + √6) / 8
(√2 + √6) / 4
Therefore Sin75°= (√2 + √6) / 4
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