find sin(a) and sec(a) when 15 cot (a)=8
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15cotA=8
then cotA=8/15
cotA=base/perpendicular
which means base=8 and perpendicular=15
by pythagoras theoram hypotenes2=perpendicular2+base2
hypotenes.sq=8.sq+15.sq
=64+225=289=17
sin(a)=p/hy=15/17
sec(a)=hy/p=17/8
then cotA=8/15
cotA=base/perpendicular
which means base=8 and perpendicular=15
by pythagoras theoram hypotenes2=perpendicular2+base2
hypotenes.sq=8.sq+15.sq
=64+225=289=17
sin(a)=p/hy=15/17
sec(a)=hy/p=17/8
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