Find sin theta *cos theta
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Step-by-step explanation:
we know,
sin²theta + cos²theta=1
now,
(sin²theta)²+(cos²theta)²=½
this is of the form a²+b²
(a+b)²=a²+b²+2ab
a²+b²=(a+b)²-2ab
(sin²theta+ cos² theta)²-2sin²thetacos²theta=½
1-2sin²theta cos²theta=½
-2sin²theta cos² theta= -½
sin²theta cos²theta= 1/4
sin theta cos theta=1/2
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