Question

find sin²52½°-sin²22½°

plzzz answer....☺

Answer 1

sin²52½° - sin²22½°

=( sin52½° + sin22½)(sin52½° -sin22½°)

={2sin(52½+ 22½)/2.cos(52½-22½)/2 }{2sin(52½-22½)/2.cos(52½+22½)/2}

={ 2×sin75/2×cos15° }{2cos75/2°.sin15°}

={2sin15°.cos15°}{2sin75/2°.cos75/2°}

=sin30° × sin75

=1/2 × sin(30+45)

=1/2 × { sin30.cos45+sin45.cos30}

=1/2 × { 1/2 × 1/√2 + 1/√2 ×√3/2 }

= (√3 + 1)/4√2

Answer 2

Answer:

answer for this question is(√3+1)/(4√2)