Math, asked by Ridimjuneja76, 5 months ago

find Sin60 *cot30-2 sec^2 45+3 cos60* tan45 -tan^2 60.​

Answers

Answered by Anonymous
56

Answer:

{ \huge{ \underline{ \bf{ \red{Question}}}}}

{ \sf{sin \: 60 \times cot \: 30 - 2 {sec}^{2} 45 + 3cos60 \times tan45 -  {tan}^{2}60 }}

Solution:-

{ \implies{ \sf{sin60 \times cot30 - 2 {sec}^{2} 45 + 3cos60 \times tan45 -  {tan}^{2} 60}}}

{ \implies{ \frac{ \sqrt{3} }{2} \times  \sqrt{3}  - 2 \times ( { \sqrt{2} }^{2} )  + 3 \times  \frac{1}{2} \times 1 -  { (\sqrt{3} }^{2} ) }}

{ \implies{ \frac{3}{2}  - 2 \times 2 +  \frac{3}{2}  \times 1 - 3 }}

{ \implies{ \frac{3}{2} - 4 +  \frac{3}{2} - 3  }}

{ \implies{ \frac{ - 5}{2} +  \frac{3}{2}   - 3}}

{ \implies{ \frac{ - 2}{2}  - 3}}

{ \implies{{ \cancel{ \frac{ - 2}{2}}} - 3 }}

{ \implies{ - 1 - 3}}

{ \implies{ - 4}}

-4 is your answer

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