Question

find sinc,cos c and tan c in the adjacent triangle bc=5cm ac=13cm

Answer 1

Answer:

we can find this by pythagoras theorem:

Step-by-step explanation:

if, b(base)=5

h(hypotenus)=13

now,

(h)²= (b)²+(p)²

(13)²=(5)²+(p)²

169=25+(p)²

169-25=(p)²

144=(p)²

12=p

now, what is sin,

sin is p/h

and what will be sinC

it is 12/13

now, what is cos,

cos is h/p

and what will be cosC

it is 13/12

Answer 2

Answer:

Adjacent Triangle

Step-by-step explanation:

Sin c= P/H

perpendicular = √(13)^2-(5)^2

= √144= 12

= 12/13

Cosc = √1-sin^2c

1-144/169= 5/13

TanC= sinc/cosc = 12/13/(5/13)

= 12/5