Question

Find slope of tangent of curve Y= x-1/x+2 at x=2. (a) 3/16 (b) 5/17 (c) 9/11 (d) None of the above

Answer 1

in order to find the slope of tangent first we have to differentiate the function w.r.t. x

y'= 1(X+2) - (x-1)/(X+2)^2

y'= X+2-x+1/(X+2)^2

y'= 3/(x+2)^2

y' at X=2 is 3/16