find smallest cube number divisible by 12,5 and 10
Answers
Answered by
0
Answer:
1 is the answer I think.. I hope it is right
Answered by
0
Answer:
27000
Step-by-step explanation:
LCM of 12,5 and 10 is 60
prime factorization of 60 is 2*2*3*5
to make the pairs, required factors = 2,3,3,5,5
multiply the factors and u will get 450
therefore smallest cube number divisible by 12,5 and 10 is 450*60 = 27000
HOPE IT WILL HELP...
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