Math, asked by ramjilalsharma11541, 9 months ago

find smallest number divided by 28 and 32 by leaving remainder 8 and 12 respectively​

Answers

Answered by drumeshsahkothia
0

Answer:

20 is the smallest number divided by 28 and 32 and leaving remainder 8 and 12 respectively

Answered by anantrajusharma
3

Answer:

204

Step-by-step explanation:

Therefore, 28–8=20 & 32–12=20 are divisible by the required number will be 20 less than the LCM of 28 and 32. Hence, the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 is 204

JAI SHREE KRISHNA

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