Question

find smallest number which must be subracted from 833 to make it a perfect cube

Answer 1

hi there,,

The smallest no. which must be substracted from 833 to make a cube of 9 is 104.
And the cube of 9 is 729.

Thanks

Answer 2

Here's your answer..

Solution:-

First,we will find the perfect cube near 833.
It can be 9 or 10
$= > 9 \times 9 \times 9 \\ = > 729$
$= > 10 \times 10 \times 10 \\ = > 1000$
Since,1000 is greater than 1000 and we have to find the least number which should to subtracted from 833 to make it perfect cube.So,we will subtract 833 by 729 instead of 1000.

So,
$= > 833 - 729 \\ = >104$
Therefore,the smallest number which must be subtracted from 833 to make it perfect cube is 104.

$= > 833 - 104 \\ = > 729$
And
$= > \sqrt{729} = 27$
This is a perfect cube now.

Hope it helps you....