find solutions √ax-√by=b-a and √bx-√ay=0
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Step-by-step explanation:
ax+by−a+b=0
x=
a
a−b−by
bx−ay−a−b=0
b(
a
a−b−by
)−ay=a+b
ab−b
2
−b
2
y−a
2
y=(a+b)a
−(a
2
+b
2
)y=a
2
+ab+b
2
−ab
y=
−(a
2
+b
2
)
a
2
+b
2
=−1
x=
a
a−b+b
=1
So x=1 & y=−1.
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