find spuare root of 484 through decomposition into prime factors
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Resolving 484 as the product of primes, we get
484 = 2 × 2 × 11 × 11
√484 = √(2 × 2 × 11 × 11)
= 2 × 11
Therefore, √484 = 22
484 = 2 × 2 × 11 × 11
√484 = √(2 × 2 × 11 × 11)
= 2 × 11
Therefore, √484 = 22
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484=2 x2 x11 x11 according to prime factorisation then√484=2 x11 =22
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