find square of (x²-3y)
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(x²- 3y)²
x⁴ - 2(x²)(3y) + 3y²
x⁴ - 6x²y + 3y²
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0
Answer:
x^4-6x^2y+9y^2
Step-by-step explanation:
(x^2-3y)^2
= (x^2)^2-2(x^2)(3y) +(3y^2)
=x^4-6x^2y+9y^2
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