Find square root of 121 and 196 by the method of repeated subtraction
Answers
Answer:
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Step-by-step explanation:
Solution :
\begin{lgathered}121 - 1 = 120 \\ 120 - 3 = 117 \\ 117 - 5 = 112 \\ 112 - 7 = 105 \\ 105 - 9 = 96 \\ 96 - 11 = 85 \\ 85 - 13 = 72 \\ 72 - 15 = 57 \\ 57 - 17 = 40 \\ 40 - 19 = 21 \\ 21 - 21 = 0\end{lgathered}
121−1=120
120−3=117
117−5=112
112−7=105
105−9=96
96−11=85
85−13=72
72−15=57
57−17=40
40−19=21
21−21=0
We have subtracted from 121, the successive odd numbers from 1 to 21 , and obtained 0 in step 11
Hence,
\sqrt{121} = 11
121
=11
Answer:
121
121-1=120
120-3 =117
117-5=112
112-7=105
105-9=96
96-11=85
85-13=72
72-15=57
57-17=40
40-19=21
21-21=0
Ans is 11
196
196-1=195
195-3 =192
192-5=187
187-7=180
180-9 =171
171-11=160
160-13=147
147-15=132
132-17=115
115-19=96
96-21=75
75-23=52
52-25=27
27-27=0
Ans is 13
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