Question

Find Square root of 3(4-6+10÷2)​

Answer 1

$\sqrt{3(4 - 6 + 10 \div 2)}$

$=> \sqrt{3(4 - 6 + 5)}$

$= > \sqrt{3(9 - 6)}$

$=> \sqrt{(3 \times 3)}$

$=> 3$

Mark my answer as brainlist if you understand my process and answer.

Answer 2

$3(4 - 6 + 10 \div 2) \\ = 3(4 - 6 + 5) \\ = 3(3) \\ = \sqrt{3 \times 3} \\ = 3$