find sum of 50 terms of ap whose second and thirs terms are 14 and 18
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hope it may help you
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an = a+(n-1)d
so, 2nd term = a+( 1-1)d=14
= a+d=14
3rd term = a +(3-1)d=18
= a+ 2d
substitute u would get
d=4 and a=10
sn=n/2 (2a+(n-1)d)
substitute u would get
answer =90
so, 2nd term = a+( 1-1)d=14
= a+d=14
3rd term = a +(3-1)d=18
= a+ 2d
substitute u would get
d=4 and a=10
sn=n/2 (2a+(n-1)d)
substitute u would get
answer =90
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